Changes between Initial Version and Version 1 of Ticket #5602, comment 8


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Timestamp:
2019-08-14T21:39:15Z (6 years ago)
Author:
Francesco Casella

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  • Ticket #5602, comment 8

    initial v1  
    1212y := 10 - x;
    1313z := -y/3;
    14 y*z = 0;
     14y*z = 10;
    1515}}}
    1616Now, the residual does not depend directly on {{{x}}}, but it does through the two assignments. If you add the differentiated equations, you get the following procedure