Changes between Initial Version and Version 1 of Ticket #4398, comment 27
- Timestamp:
- 2017-10-26T17:08:10Z (7 years ago)
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Ticket #4398, comment 27
initial v1 6 6 > And it would be `O(N*K*(log(N)+log(K)))` for a binary tree; 7 7 8 No matter how large K is, O(N*K*(log(N)+log(K))) is always better than O(N^2 ) for sufficiently large N.8 No matter how large K is, O(N*K*(log(N)+log(K))) is always better than O(N^2^) for sufficiently large N.