#1692 closed defect (fixed)
Non-linear system causes stack protection issues
| Reported by: | Martin Sjölund | Owned by: | Martin Sjölund |
|---|---|---|---|
| Priority: | high | Milestone: | 1.9.0 |
| Component: | Backend | Version: | |
| Keywords: | Cc: | Martin Sjölund, Frenkel, TUD, Willi Braun |
Description (last modified by )
http://openmodelica.org/index.php?option=com_agora&task=topic&id=526&Itemid=87
package Medium
function h_pt
input Real p;
input Real t;
output Real h;
algorithm
h := t;
end h_pt;
function d_ph
input Real p;
input Real h;
output Real d;
algorithm
d := h;
end d_ph;
end Medium;
connector Port
flow Real mf;
Real p;
stream Real h;
end Port;
model Pipe
Port port_a, port_b;
Real loopPressure;
protected
Real density;
Real outputPressure;
function func
input Real inputPressure;
input Real density;
output Real outputPressure;
output Real loopPressure;
algorithm
loopPressure := inputPressure;
outputPressure := inputPressure;
end func;
equation
density = Medium.d_ph(port_a.p, port_a.h);
(outputPressure, loopPressure) = func(port_a.p, density);
port_a.mf + port_b.mf = 0;
port_b.p = outputPressure;
port_a.h = inStream(port_b.h);
port_b.h = inStream(port_a.h);
end Pipe;
model Split
Port port_a, port_b, port_c;
equation
connect(port_a, port_b);
connect(port_a, port_c);
end Split;
model Join
Port port_a, port_b, port_c;
final parameter Real epsFlow = 1e-15;
equation
port_a.mf + port_b.mf + port_c.mf = 0;
port_b.p = min(port_a.p, port_c.p);
port_a.h = (max(port_b.mf, epsFlow) * inStream(port_b.h) + max(port_c.mf, epsFlow) * inStream(port_c.h)) / (max(port_b.mf, epsFlow) + max(port_c.mf, epsFlow));
port_b.h = (max(port_a.mf, epsFlow) * inStream(port_a.h) + max(port_c.mf, epsFlow) * inStream(port_c.h)) / (max(port_a.mf, epsFlow) + max(port_c.mf, epsFlow));
port_c.h = (max(port_a.mf, epsFlow) * inStream(port_a.h) + max(port_b.mf, epsFlow) * inStream(port_b.h)) / (max(port_a.mf, epsFlow) + max(port_b.mf, epsFlow));
end Join;
model Boundary
Port port;
Real t;
Real mf;
Real p;
equation
port.mf = mf;
port.p = p;
port.h = Medium.h_pt(p, t);
end Boundary;
model Test
Split[numberOfSplits - 1] split;
Join[numberOfSplits - 1] join;
Pipe[numberOfSplits] pipe;
Boundary source;
Boundary sink;
parameter Integer numberOfSplits = 2;
parameter Integer numberOfLoops = 10;
equation
source.mf = -10;
source.p = 100000;
source.t = 300;
sink.t = 300;
// Grid:
// split
// --+--+---
// | | | pipe
// --+--+---
// join
connect(source.port, split[1].port_a);
for i in 1:numberOfSplits - 1 loop
connect(split[i].port_c, pipe[i].port_a);
connect(pipe[i].port_b, join[i].port_c);
split[i].port_c.mf = -source.port.mf / numberOfSplits;
end for;
for i in 1:numberOfSplits - 2 loop
connect(split[i].port_b, split[i + 1].port_a);
connect(join[i + 1].port_b, join[i].port_a);
end for;
connect(split[numberOfSplits - 1].port_b, pipe[numberOfSplits].port_a);
connect(pipe[numberOfSplits].port_b, join[numberOfSplits - 1].port_a);
connect(join[1].port_b, sink.port);
end Test;
$ MODELICAUSERCFLAGS="-g -fstack-protector" omc +s +simCodeTarget=Dump a.mo | grep residual | wc -l 16
$ MODELICAUSERCFLAGS="-g -fstack-protector" omc +s +simCodeTarget=Dump a.mo | grep nonlinear | tr , \\n | cut -d: -f2 | tr -d " " | wc -l 12
So we have 16 residual expressions written to 12 memory locations. WRONG WRONG WRONG.
Also, many of the expressions are KNOWN ZERO!
residual: xloc[2]; residual: xloc[1]; residual: xloc[11] - Medium.d_ph(100000.0,xloc[10]); residual: xloc[9] + (-0.9999999999999998 * source.port.h + -0.00000000000000009999999999999999 * xloc[10]); residual: xloc[10] + -0.5 * (xloc[8] + xloc[9]); residual: xloc[6] + (-0.9999999999999999 * xloc[7] + -0.00000000000000006666666666666667 * xloc[8]); residual: xloc[7] + (-0.6666666666666666 * source.port.h + -0.3333333333333333 * xloc[6]); residual: xloc[5] - Medium.d_ph(100000.0,xloc[6]); residual: xloc[3]; residual: xloc[4]; residual: xloc[3]; residual: xloc[4]; residual: xloc[0] - min(xloc[2],xloc[3]); residual: xloc[2]; residual: xloc[1]; residual: xloc[8] - Medium.h_pt(xloc[0],300.0);
We can replace xloc[1]=xloc[2]=xloc[4]=xloc[3]=0 since this is a trivial solution (and the only correct one). We can then replace all these variables with the known constant (like removeSimpleExpressions), and re-run SCC algorithm since this may no longer be a SCC :)
In this case:
residual: xloc[11] - Medium.d_ph(100000.0,xloc[10]); residual: xloc[9] + (-0.9999999999999998 * source.port.h + -0.00000000000000009999999999999999 * xloc[10]); residual: xloc[10] + -0.5 * (xloc[8] + xloc[9]); residual: xloc[6] + (-0.9999999999999999 * xloc[7] + -0.00000000000000006666666666666667 * xloc[8]); residual: xloc[7] + (-0.6666666666666666 * source.port.h + -0.3333333333333333 * xloc[6]); residual: xloc[5] - Medium.d_ph(100000.0,xloc[6]); residual: xloc[0] - 0.0; residual: xloc[8] - Medium.h_pt(xloc[0],300.0);
In this case (re-run xloc[0]=0:
residual: xloc[11] - Medium.d_ph(100000.0,xloc[10]); residual: xloc[9] + (-0.9999999999999998 * source.port.h + -0.00000000000000009999999999999999 * xloc[10]); residual: xloc[10] + -0.5 * (xloc[8] + xloc[9]); residual: xloc[6] + (-0.9999999999999999 * xloc[7] + -0.00000000000000006666666666666667 * xloc[8]); residual: xloc[7] + (-0.6666666666666666 * source.port.h + -0.3333333333333333 * xloc[6]); residual: xloc[5] - Medium.d_ph(100000.0,xloc[6]); residual: xloc[8] - Medium.h_pt(0.0,300.0); /* Another known constant! */
In this case (re-run xloc[8]=300.0):
residual: xloc[11] - Medium.d_ph(100000.0,xloc[10]); residual: xloc[9] + (-0.9999999999999998 * source.port.h + -0.00000000000000009999999999999999 * xloc[10]); residual: xloc[10] + -0.5 * (300.0 + xloc[9]); residual: xloc[6] + (-0.9999999999999999 * xloc[7] + -0.00000000000000006666666666666667 * 300.0); residual: xloc[7] + (-0.6666666666666666 * source.port.h + -0.3333333333333333 * xloc[6]); residual: xloc[5] - Medium.d_ph(100000.0,xloc[6]);
Much simpler to solve :) Feel free to split this into 2 different bugs if needed.
Re-sort:
Linear (?): residual: xloc[9] + (-0.9999999999999998 * source.port.h + -0.00000000000000009999999999999999 * xloc[10]); residual: xloc[10] + -0.5 * (300.0 + xloc[9]); Scalar: residual: xloc[11] = Medium.d_ph(100000.0,xloc[10]); Linear (?): residual: xloc[6] + (-0.9999999999999999 * xloc[7] + -0.00000000000000006666666666666667 * 300.0); residual: xloc[7] + (-0.6666666666666666 * source.port.h + -0.3333333333333333 * xloc[6]); Scalar: residual: xloc[5] = Medium.d_ph(100000.0,xloc[6]);
This equation system screams: Please make me faster, Willi and/or Jens
Attachments (1)
Change History (7)
comment:1 by , 14 years ago
comment:2 by , 13 years ago
| Cc: | added; removed |
|---|---|
| Component: | → Backend |
| Description: | modified (diff) |
comment:3 by , 13 years ago
| Description: | modified (diff) |
|---|
by , 13 years ago
| Attachment: | Test1692.mo added |
|---|
comment:4 by , 13 years ago
Now with tearing the system is reduced to size 4 (from size 12), so I asume the problem is solved.
torn nonlinear Equationsystem:
1: pipe[2].outputPressure:VARIABLE(protected = true ) .Test, .Pipe, .Real type: Real [2]
2: pipe[2].loopPressure:VARIABLE() .Test, .Pipe, .Real type: Real [2]
3: split[1].port_c.h:VARIABLE() .Test, .Split, .Port, .Real type: Real [1]
4: pipe[1].outputPressure:VARIABLE(protected = true ) .Test, .Pipe, .Real type: Real [2]
5: pipe[1].loopPressure:VARIABLE() .Test, .Pipe, .Real type: Real [2]
6: sink.p:VARIABLE() .Test, .Boundary, .Real type: Real
7: split[1].port_b.h:VARIABLE() .Test, .Split, .Port, .Real type: Real [1]
8: sink.port.h:VARIABLE() .Test, .Boundary, .Port, .Real type: Real
1: join[1].port_c.h:VARIABLE() .Test, .Join, .Port, .Real type: Real [1]
2: join[1].port_a.h:VARIABLE() .Test, .Join, .Port, .Real type: Real [1]
3: pipe[1].density:VARIABLE(protected = true ) .Test, .Pipe, .Real type: Real [2]
4: pipe[2].density:VARIABLE(protected = true ) .Test, .Pipe, .Real type: Real [2]
1 : pipe[2].outputPressure := $_start(pipe[2].outputPressure);
pipe[2].loopPressure := $_start(pipe[2].loopPressure);
(pipe[2].outputPressure, pipe[2].loopPressure) := Pipe.func(100000.0, pipe[2].density);
2 : split[1].port_c.h = 1.0 * source.port.h + 1e-16 * join[1].port_a.h
3 : pipe[1].outputPressure := $_start(pipe[1].outputPressure);
pipe[1].loopPressure := $_start(pipe[1].loopPressure);
(pipe[1].outputPressure, pipe[1].loopPressure) := Pipe.func(100000.0, pipe[1].density);
4 : sink.p = min(pipe[2].outputPressure, pipe[1].outputPressure)
5 : split[1].port_b.h = 0.666666666666667 * source.port.h + 0.333333333333333 * join[1].port_c.h
6 : sink.port.h = Medium.h_pt(sink.p, 300.0)
1 : join[1].port_c.h = 1.0 * split[1].port_b.h + 6.66666666666667e-17 * sink.port.h
2 : pipe[1].density = Medium.d_ph(100000.0, join[1].port_c.h)
3 : join[1].port_a.h = 0.5 * (sink.port.h + split[1].port_c.h)
4 : pipe[2].density = Medium.d_ph(100000.0, join[1].port_a.h)
comment:6 by , 13 years ago
| Milestone: | → 1.9.0 |
|---|

After a closer look at the equations the matching algorithm seems to produce a bad solution because some variables should be solved as function inputs. Reordering the system by hand shows a sulution without solving variables as function inputs:
split\[1].port_a.h = 2e-016 * join[1].port_a.h + 1.0 * join[1].port_c.h
join[1].port_b.h = 1.0 * split[1].port_b.h + 6.66666666666667e-017 * split[1].port_c.h
(pipe[1].outputPressure, pipe[1].loopPressure) := Pipe.func(100000.0,pipe[1].density)
(pipe[2].outputPressure, pipe[2].loopPressure) := Pipe.func(100000.0,pipe[2].density)
sink.port.h = Medium.h_pt(sink.p,300.0)
sink.p = min(pipe[2].outputPressure,pipe[1].outputPressure)
pipe[1].density = Medium.d_ph(100000.0,join[1].port_c.h)
pipe[2].density = Medium.d_ph(100000.0,join[1].port_a.h)
split[1].port_b.h = 0.666666666666667 * source.port.h + 0.333333333333333 * join[1].port_c.h
join[1].port_c.h = 1.0 * split[1].port_b.h + 6.66666666666667e-017 * sink.port.h
split[1].port_c.h = 1.0 * source.port.h + 1e-016 * join[1].port_a.h
join[1].port_a.h = 0.5 * (sink.port.h + split[1].port_c.h)
Looks like the function transforming the equations to residual form fails.