Opened 14 years ago
Last modified 13 years ago
#1692 closed defect
Non-linear system causes stack protection issues — at Version 2
| Reported by: | Martin Sjölund | Owned by: | Martin Sjölund | 
|---|---|---|---|
| Priority: | high | Milestone: | 1.9.0 | 
| Component: | Backend | Version: | |
| Keywords: | Cc: | Martin Sjölund, Frenkel, TUD, Willi Braun | 
Description (last modified by )
http://openmodelica.org/index.php?option=com_agora&task=topic&id=526&Itemid=87
package Medium 
  function h_pt 
    input Real p; 
    input Real t; 
    output Real h; 
  algorithm 
    h := t; 
  end h_pt; 
  
  function d_ph 
    input Real p; 
    input Real h; 
    output Real d; 
  algorithm 
    d := h; 
  end d_ph;  
end Medium; 
connector Port 
  flow Real mf; 
  Real p; 
  stream Real h; 
end Port; 
model Pipe 
  Port port_a, port_b; 
  Real loopPressure; 
    
protected 
  Real density; 
  Real outputPressure; 
  
  function func 
    input Real inputPressure; 
    input Real density; 
    output Real outputPressure; 
    output Real loopPressure; 
  algorithm 
    loopPressure := inputPressure; 
    outputPressure := inputPressure; 
  end func; 
equation 
  density = Medium.d_ph(port_a.p, port_a.h); 
  (outputPressure, loopPressure) = func(port_a.p, density); 
  port_a.mf + port_b.mf = 0; 
  port_b.p = outputPressure; 
  port_a.h = inStream(port_b.h); 
  port_b.h = inStream(port_a.h); 
end Pipe; 
model Split 
  Port port_a, port_b, port_c; 
equation 
  connect(port_a, port_b); 
  connect(port_a, port_c);  
end Split; 
model Join 
  Port port_a, port_b, port_c; 
  final parameter Real epsFlow = 1e-15; 
equation 
  port_a.mf + port_b.mf + port_c.mf = 0; 
  port_b.p = min(port_a.p, port_c.p); 
  port_a.h = (max(port_b.mf, epsFlow) * inStream(port_b.h) + max(port_c.mf, epsFlow) * inStream(port_c.h)) / (max(port_b.mf, epsFlow) + max(port_c.mf, epsFlow)); 
  port_b.h = (max(port_a.mf, epsFlow) * inStream(port_a.h) + max(port_c.mf, epsFlow) * inStream(port_c.h)) / (max(port_a.mf, epsFlow) + max(port_c.mf, epsFlow)); 
  port_c.h = (max(port_a.mf, epsFlow) * inStream(port_a.h) + max(port_b.mf, epsFlow) * inStream(port_b.h)) / (max(port_a.mf, epsFlow) + max(port_b.mf, epsFlow)); 
end Join;  
model Boundary 
  Port port; 
  Real t; 
  Real mf; 
  Real p; 
equation 
  port.mf = mf; 
  port.p = p; 
  port.h = Medium.h_pt(p, t); 
end Boundary; 
model Test 
  Split[numberOfSplits - 1] split; 
  Join[numberOfSplits - 1] join;                                                                  
  Pipe[numberOfSplits] pipe; 
    
  Boundary source; 
  Boundary sink; 
    
  parameter Integer numberOfSplits = 2;    
  parameter Integer numberOfLoops = 10; 
    
equation  
  source.mf = -10; 
  source.p = 100000; 
  source.t = 300; 
  sink.t = 300; 
  
  // Grid: 
  //  split 
  // --+--+--- 
  //   |  |  | pipe 
  // --+--+--- 
  //  join 
  
  connect(source.port, split[1].port_a); 
  
  for i in 1:numberOfSplits - 1 loop 
    connect(split[i].port_c, pipe[i].port_a); 
    connect(pipe[i].port_b, join[i].port_c); 
    split[i].port_c.mf = -source.port.mf / numberOfSplits;    
  end for; 
  
  
  for i in 1:numberOfSplits - 2 loop 
    connect(split[i].port_b, split[i + 1].port_a); 
    connect(join[i + 1].port_b, join[i].port_a); 
  end for;  
    
  connect(split[numberOfSplits - 1].port_b, pipe[numberOfSplits].port_a); 
  connect(pipe[numberOfSplits].port_b, join[numberOfSplits - 1].port_a); 
  
  connect(join[1].port_b, sink.port); 
end Test; }}}
{{{$ MODELICAUSERCFLAGS="-g -fstack-protector" omc +s +simCodeTarget=Dump a.mo | grep residual | wc -l
16
$ MODELICAUSERCFLAGS="-g -fstack-protector" omc +s +simCodeTarget=Dump a.mo | grep nonlinear | tr , \\n | cut -d: -f2 | tr -d " " | wc -l 12
So we have 16 residual expressions written to 12 memory locations. WRONG WRONG WRONG.
Also, many of the expressions are KNOWN ZERO!
residual: xloc[2]; residual: xloc[1]; residual: xloc[11] - Medium.d_ph(100000.0,xloc[10]); residual: xloc[9] + (-0.9999999999999998 * source.port.h + -0.00000000000000009999999999999999 * xloc[10]); residual: xloc[10] + -0.5 * (xloc[8] + xloc[9]); residual: xloc[6] + (-0.9999999999999999 * xloc[7] + -0.00000000000000006666666666666667 * xloc[8]); residual: xloc[7] + (-0.6666666666666666 * source.port.h + -0.3333333333333333 * xloc[6]); residual: xloc[5] - Medium.d_ph(100000.0,xloc[6]); residual: xloc[3]; residual: xloc[4]; residual: xloc[3]; residual: xloc[4]; residual: xloc[0] - min(xloc[2],xloc[3]); residual: xloc[2]; residual: xloc[1]; residual: xloc[8] - Medium.h_pt(xloc[0],300.0);
We can replace xloc[1]=xloc[2]=xloc[4]=xloc[3]=0 since this is a trivial solution (and the only correct one). We can then replace all these variables with the known constant (like removeSimpleExpressions), and re-run SCC algorithm since this may no longer be a SCC :)
In this case:
residual: xloc[11] - Medium.d_ph(100000.0,xloc[10]); residual: xloc[9] + (-0.9999999999999998 * source.port.h + -0.00000000000000009999999999999999 * xloc[10]); residual: xloc[10] + -0.5 * (xloc[8] + xloc[9]); residual: xloc[6] + (-0.9999999999999999 * xloc[7] + -0.00000000000000006666666666666667 * xloc[8]); residual: xloc[7] + (-0.6666666666666666 * source.port.h + -0.3333333333333333 * xloc[6]); residual: xloc[5] - Medium.d_ph(100000.0,xloc[6]); residual: xloc[0] - 0.0; residual: xloc[8] - Medium.h_pt(xloc[0],300.0);
In this case (re-run xloc[0]=0:
residual: xloc[11] - Medium.d_ph(100000.0,xloc[10]); residual: xloc[9] + (-0.9999999999999998 * source.port.h + -0.00000000000000009999999999999999 * xloc[10]); residual: xloc[10] + -0.5 * (xloc[8] + xloc[9]); residual: xloc[6] + (-0.9999999999999999 * xloc[7] + -0.00000000000000006666666666666667 * xloc[8]); residual: xloc[7] + (-0.6666666666666666 * source.port.h + -0.3333333333333333 * xloc[6]); residual: xloc[5] - Medium.d_ph(100000.0,xloc[6]); residual: xloc[8] - Medium.h_pt(0.0,300.0); /* Another known constant! */
In this case (re-run xloc[8]=300.0):
residual: xloc[11] - Medium.d_ph(100000.0,xloc[10]); residual: xloc[9] + (-0.9999999999999998 * source.port.h + -0.00000000000000009999999999999999 * xloc[10]); residual: xloc[10] + -0.5 * (300.0 + xloc[9]); residual: xloc[6] + (-0.9999999999999999 * xloc[7] + -0.00000000000000006666666666666667 * 300.0); residual: xloc[7] + (-0.6666666666666666 * source.port.h + -0.3333333333333333 * xloc[6]); residual: xloc[5] - Medium.d_ph(100000.0,xloc[6]);
Much simpler to solve :) Feel free to split this into 2 different bugs if needed.
Re-sort:
Linear (?): residual: xloc[9] + (-0.9999999999999998 * source.port.h + -0.00000000000000009999999999999999 * xloc[10]); residual: xloc[10] + -0.5 * (300.0 + xloc[9]); Scalar: residual: xloc[11] = Medium.d_ph(100000.0,xloc[10]); Linear (?): residual: xloc[6] + (-0.9999999999999999 * xloc[7] + -0.00000000000000006666666666666667 * 300.0); residual: xloc[7] + (-0.6666666666666666 * source.port.h + -0.3333333333333333 * xloc[6]); Scalar: residual: xloc[5] = Medium.d_ph(100000.0,xloc[6]);
This equation system screams: Please make me faster, Willi and/or Jens
Change History (2)
comment:1 by , 14 years ago
comment:2 by , 13 years ago
| Cc: | added; removed | 
|---|---|
| Component: | → Backend | 
| Description: | modified (diff) | 


After a closer look at the equations the matching algorithm seems to produce a bad solution because some variables should be solved as function inputs. Reordering the system by hand shows a sulution without solving variables as function inputs:
split\[1].port_a.h = 2e-016 * join[1].port_a.h + 1.0 * join[1].port_c.h
join[1].port_b.h = 1.0 * split[1].port_b.h + 6.66666666666667e-017 * split[1].port_c.h
(pipe[1].outputPressure, pipe[1].loopPressure) := Pipe.func(100000.0,pipe[1].density)
(pipe[2].outputPressure, pipe[2].loopPressure) := Pipe.func(100000.0,pipe[2].density)
sink.port.h = Medium.h_pt(sink.p,300.0)
sink.p = min(pipe[2].outputPressure,pipe[1].outputPressure)
pipe[1].density = Medium.d_ph(100000.0,join[1].port_c.h)
pipe[2].density = Medium.d_ph(100000.0,join[1].port_a.h)
split[1].port_b.h = 0.666666666666667 * source.port.h + 0.333333333333333 * join[1].port_c.h
join[1].port_c.h = 1.0 * split[1].port_b.h + 6.66666666666667e-017 * sink.port.h
split[1].port_c.h = 1.0 * source.port.h + 1e-016 * join[1].port_a.h
join[1].port_a.h = 0.5 * (sink.port.h + split[1].port_c.h)
Looks like the function transforming the equations to residual form fails.